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Class 6th Chapters
1. Knowing Our Numbers 2. Whole Numbers 3. Playing With Numbers
4. Basic Geometrical Ideas 5. Understanding Elementary Shapes 6. Integers
7. Fractions 8. Decimals 9. Data Handling
10. Mensuration 11. Algebra 12. Ratio And Proportion
13. Symmetry 14. Practical Geometry

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Introduction to Ratio Introduction to Proportion Unitary Method


Chapter 12 Ratio And Proportion (Concepts)

Welcome to Chapter 12: Ratio and Proportion! This chapter introduces powerful ways to compare quantities and understand relationships between them. Have you ever wanted to compare the number of boys and girls in your class, or figure out if a recipe will taste the same if you use more ingredients? Ratio and proportion help us do exactly that! We'll also learn a very handy technique called the Unitary Method for solving everyday problems involving cost, distance, and more. These are really practical tools used in shopping, cooking, map reading, and many other situations.

First, let's understand Ratio. A ratio is used to compare two quantities of the same kind by using division. For example, if there are 10 apples and 5 oranges in a basket, the ratio of apples to oranges is 10 compared to 5. We write this as 10:5 or as a fraction $\frac{10}{5}$. It's important that the quantities we compare are in the same units (we compare lengths in cm to lengths in cm, not cm to meters, unless we convert them first!). Just like fractions, ratios can often be simplified. The ratio 10:5 can be simplified to 2:1 by dividing both parts by their Highest Common Factor (HCF), which is 5. This means for every 1 orange, there are 2 apples. We will also learn how to compare different ratios to see which one represents a larger or smaller comparison, often by converting them to equivalent fractions with the same denominator (using LCM).

Next, we explore Proportion. Proportion is simply a statement that says two ratios are equal or equivalent. If the ratio of $a$ to $b$ is the same as the ratio of $c$ to $d$, we say that $a, b, c, d$ are in proportion. We write this as $a:b :: c:d$, which is read as "a is to b as c is to d". In a proportion, the first and last terms ($a$ and $d$) are called the extremes, and the middle terms ($b$ and $c$) are called the means. There's a fundamental rule for proportions: the product of the extremes is equal to the product of the means. That is, $a \times d = b \times c$. This rule is super useful! We can use it to check if four numbers are truly in proportion, or if we know three terms in a proportion, we can use this rule to find the missing fourth term.

Finally, we learn a very practical problem-solving technique called the Unitary Method. The idea is simple: if you know the value or cost of several items, you first figure out the value of one item (by dividing), and then you can easily find the value of any number of items (by multiplying). For example, if 5 apples cost $\textsf{₹}50$, the unitary method helps us find the cost of 1 apple first ($\textsf{₹}50 \div 5 = \textsf{₹}10$). Once we know the cost of one apple, we can find the cost of any number, say 7 apples ($\textsf{₹}10 \times 7 = \textsf{₹}70$). We'll practice using the unitary method to solve various everyday problems involving costs, distances traveled, time taken, etc. This chapter equips you with essential skills for making comparisons and solving practical rate problems.



Introduction to Ratio

In earlier chapters, we learned about numbers, integers, fractions, decimals, and how to perform operations on them. We also looked at how to compare numbers and quantities. This chapter introduces a new and powerful way to compare quantities: using Ratio. Understanding ratios will help us relate different amounts and solve various real-life problems. We will then extend this concept to Proportion and the Unitary Method.


What is a Ratio?

In everyday life, we often compare quantities. For example, we might say one person is taller than another, or one bag of rice is heavier than another. Ratio provides a specific way to compare two quantities. A Ratio is a comparison of two quantities of the same kind and in the same units by using division.

Example: Suppose a class has 20 girls and 15 boys. We can compare the number of girls to the number of boys. The ratio of the number of girls to the number of boys is the number of girls divided by the number of boys.

Ratio $= \frac{\text{Number of girls}}{\text{Number of boys}} = \frac{20}{15}$

This fraction can be simplified by dividing both the numerator and the denominator by their Highest Common Factor (HCF), which is 5.

Ratio $= \frac{20 \div 5}{15 \div 5} = \frac{4}{3}$

A ratio is usually written using a colon ($:$). The ratio of 20 to 15 is written as $20:15$. The simplified ratio is $4:3$. This means for every 4 girls in the class, there are 3 boys.

The ratio $a$ to $b$ is written as $a:b$ or as a fraction $\frac{a}{b}$ (where $b \neq 0$).


Terms of a Ratio

In the ratio $a:b$, the two numbers $a$ and $b$ are called the Terms of the ratio.

Example: In the ratio $4:3$ (from the girls to boys example), $4$ is the antecedent and $3$ is the consequent.

Example: In the ratio $3:5$, $3$ is the antecedent and $5$ is the consequent.


Important Points about Ratio

To correctly understand and use ratios, keep the following points in mind:


Finding Ratio in Simplest Form

To express a ratio in its simplest form, find the HCF of the antecedent and the consequent, and divide both terms by the HCF. This is equivalent to reducing the fraction $\frac{\text{Antecedent}}{\text{Consequent}}$ to its lowest terms.

Example: Find the ratio of 40 minutes to 1 hour in simplest form.

Step 1: Ensure the quantities are in the same units.

Convert 1 hour to minutes: $1 \text{ hour} = 60 \text{ minutes}$.

The quantities are 40 minutes and 60 minutes.

Step 2: Write the ratio.

Ratio $= 40 \text{ minutes} : 60 \text{ minutes} = 40:60$.

Step 3: Simplify the ratio by finding the HCF of the terms (40 and 60) and dividing both terms by the HCF.

Factors of 40: 1, 2, 4, 5, 8, 10, 20, 40

Factors of 60: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60

The HCF of 40 and 60 is 20.

Divide both terms by 20:

Antecedent: $40 \div 20 = 2$

Consequent: $60 \div 20 = 3$

The ratio in simplest form is $2:3$.


Example 1. There are 20 girls and 15 boys in a class.

(a) What is the ratio of the number of girls to the number of boys?

(b) What is the ratio of the number of girls to the total number of students in the class?

Answer:

Given:

Number of girls = 20

Number of boys = 15

First, find the total number of students in the class:

Total number of students = Number of girls + Number of boys $= 20 + 15 = 35$.


(a) We need to find the ratio of the number of girls to the number of boys.

Ratio $=$ Number of girls : Number of boys

Ratio $= 20 : 15$

To express this ratio in simplest form, find the HCF of 20 and 15.

Factors of 20: 1, 2, 4, 5, 10, 20

Factors of 15: 1, 3, 5, 15

The HCF of 20 and 15 is 5.

Divide both terms of the ratio by 5:

Antecedent: $20 \div 5 = 4$

Consequent: $15 \div 5 = 3$

The ratio of the number of girls to the number of boys is $4:3$.


(b) We need to find the ratio of the number of girls to the total number of students in the class.

Ratio $=$ Number of girls : Total number of students

Ratio $= 20 : 35$

To express this ratio in simplest form, find the HCF of 20 and 35.

Factors of 20: 1, 2, 4, 5, 10, 20

Factors of 35: 1, 5, 7, 35

The HCF of 20 and 35 is 5.

Divide both terms of the ratio by 5:

Antecedent: $20 \div 5 = 4$

Consequent: $35 \div 5 = 7$

The ratio of the number of girls to the total number of students is $4:7$.



Introduction to Proportion

In the previous section, we learned about ratio as a way to compare two quantities of the same kind and in the same units by division. Now, we will extend this concept to situations where we compare two ratios. When two ratios are equal, we say they are in Proportion.


What is Proportion?

Proportion is a statement of equality between two ratios. If two ratios are equal, they are said to be in proportion. This means that the relationship between the first pair of quantities is the same as the relationship between the second pair of quantities.

We use the symbol '::' or '=' to indicate that two ratios are in proportion.

For example, consider the ratio $2:3$. The fraction form is $\frac{2}{3}$. Now consider the ratio $4:6$. The fraction form is $\frac{4}{6}$. If we simplify the fraction $\frac{4}{6}$ by dividing the numerator and denominator by 2, we get $\frac{2}{3}$. Since $\frac{2}{3}$ is equal to $\frac{4}{6}$, the ratio $2:3$ is equal to the ratio $4:6$.

Therefore, the numbers 2, 3, 4, and 6 are in proportion. This can be written in two ways:

Both notations mean the same thing: the ratio of 2 to 3 is equal to the ratio of 4 to 6. When we write $2:3 :: 4:6$, we usually read it as "2 is to 3 as 4 is to 6".

In general, four numbers $a, b, c,$ and $d$ are in proportion if the ratio $a:b$ is equal to the ratio $c:d$. That is, $a:b :: c:d \iff \frac{a}{b} = \frac{c}{d}$.

Note: For the proportion $a:b :: c:d$ to be meaningful, $a, b, c,$ and $d$ should be non-zero quantities, and $a$ and $b$ must be of the same kind and in the same units, and $c$ and $d$ must also be of the same kind and in the same units. The kind of quantities $a, b$ can be different from the kind of quantities $c, d$ (e.g., ratio of lengths = ratio of costs), but within each ratio, the quantities must be of the same kind and unit.


Terms of a Proportion

When four quantities $a, b, c,$ and $d$ are in proportion, written as $a:b :: c:d$, these four quantities are called the Terms of the Proportion.

These terms have specific names based on their position:

In $a : b :: c : d$, we have:

$\underbrace{a}_{\text{Extreme}} : \underbrace{b}_{\text{Mean}} :: \underbrace{c}_{\text{Mean}} : \underbrace{d}_{\text{Extreme}}$


Rule of Proportion (Product of Extremes and Means)

There is a fundamental rule that holds true for any proportion. If four quantities are in proportion, the product of the extreme terms is equal to the product of the middle terms.

If $a:b :: c:d$, then it means $\frac{a}{b} = \frac{c}{d}$.

By cross-multiplication (multiplying the numerator of the first fraction by the denominator of the second and vice versa), we get:

$a \times d = b \times c$

This is the Rule of Proportion:

$\text{Product of Extremes} = \text{Product of Means}$

This rule is extremely important. It allows us to check if two ratios are equal and to find a missing term in a proportion if the other three terms are known.


Checking for Proportion

To check if four numbers $a, b, c,$ and $d$ are in proportion (in that order, i.e., if $a:b :: c:d$), we can use the Rule of Proportion. Calculate the product of the extremes ($a \times d$) and the product of the means ($b \times c$). If the two products are equal, then the numbers are in proportion; otherwise, they are not.

Example: Are the numbers 3, 4, 6, and 8 in proportion?

We need to check if $3:4 :: 6:8$ is true.

Since the Product of Extremes ($24$) is equal to the Product of Means ($24$), the numbers 3, 4, 6, and 8 are in proportion.

Example: Are the numbers 2, 3, 5, and 6 in proportion?

We need to check if $2:3 :: 5:6$ is true.

Since the Product of Extremes ($12$) is NOT equal to the Product of Means ($15$), the numbers 2, 3, 5, and 6 are NOT in proportion.


Finding a Missing Term in Proportion

The Rule of Proportion ($a \times d = b \times c$) is very useful when we know three terms of a proportion and need to find the fourth, unknown term. We can represent the unknown term by a variable (like $x$) and then use the rule to form an equation and solve for the variable.

Example: Find the missing term in the proportion $5:10 :: x:30$.

The four terms are $a=5, b=10, c=x, d=30$.

The extremes are the first and fourth terms: 5 and 30.

The means are the second and third terms: 10 and $x$.

Using the Rule of Proportion: Product of Extremes = Product of Means.

$5 \times 30 = 10 \times x$

Calculate the product on the left side:

$150 = 10x$

To find the value of $x$, we need to isolate $x$. Since $x$ is being multiplied by 10, we do the inverse operation, which is division. Divide both sides of the equation by 10 to maintain the equality:

$x = \frac{150}{10}$

Perform the division:

$x = 15$

So, the missing term is 15. The proportion is $5:10 :: 15:30$.

We can check our answer: Product of extremes $= 5 \times 30 = 150$. Product of means $= 10 \times 15 = 150$. Since $150 = 150$, the proportion is true.


Example 1. Check if the ratios $25 \text{ g} : 30 \text{ g}$ and $\textsf{₹}40 : \textsf{₹}48$ are in proportion.

Answer:

To check if two ratios are in proportion, we can compare their simplified forms or use the Rule of Proportion on the four terms.

Method 1: Comparing Simplified Ratios

Ratio 1: $25 \text{ g} : 30 \text{ g}$. The quantities are of the same kind (mass) and in the same units (grams). The ratio is $25:30$.

Simplify the ratio $25:30$: Find the HCF of 25 and 30. HCF(25, 30) = 5.

Divide both terms by 5: $25 \div 5 = 5$, $30 \div 5 = 6$.

The simplified ratio is $5:6$.


Ratio 2: $\textsf{₹}40 : \textsf{₹}48$. The quantities are of the same kind (money) and in the same units (Rupees). The ratio is $40:48$.

Simplify the ratio $40:48$: Find the HCF of 40 and 48. HCF(40, 48) = 8.

Divide both terms by 8: $40 \div 8 = 5$, $48 \div 8 = 6$.

The simplified ratio is $5:6$.


Since the simplified form of both ratios is $5:6$, the two ratios are equal. Therefore, $25 \text{ g} : 30 \text{ g}$ and $\textsf{₹}40 : \textsf{₹}48$ are in proportion.

$25 \text{ g} : 30 \text{ g} :: \textsf{₹}40 : \textsf{₹}48$

Method 2: Using the Rule of Proportion

We need to check if the four numbers 25, 30, 40, and 48 are in proportion in the order $25:30 :: 40:48$.

Identify the extremes: First term = 25, Fourth term = 48. Product of extremes $= 25 \times 48$.

Identify the means: Second term = 30, Third term = 40. Product of means $= 30 \times 40$.

Calculate the product of extremes:

$ \begin{array}{cc} & & 2 & 5 \\ & \times & 4 & 8 \\ \hline & 2 &0&0 \\ 1&0&0 & \times \\ \hline 1&2&0&0 \\ \hline \end{array} $

Product of extremes $= 1200$.

Calculate the product of means:

Product of means $= 30 \times 40 = 1200$

Compare the products:

Product of Extremes $= 1200$

Product of Means $= 1200$

Since the Product of Extremes is equal to the Product of Means ($1200 = 1200$), the ratios are in proportion.



Unitary Method

In the previous sections, we learned about ratios and proportions, which are used to compare quantities and state the equality of ratios. Now, we will learn about a practical method for solving problems involving quantities that vary in direct proportion. This method is called the Unitary Method.


What is the Unitary Method?

The term 'unitary' is derived from the word 'unit', meaning 'one'. The Unitary Method is a technique used to find the value of a desired number of units when the value of a given number of units is known. The core idea is to first find the value of a single, individual unit, and then use that value to calculate the value for the required quantity.

This method is based on the principle of direct proportion, where if you increase the number of items, the total cost (or quantity, distance, etc.) also increases proportionally, and if you decrease the number of items, the total cost decreases proportionally. This means the cost per item (value per unit) remains constant.

The unitary method typically involves two key steps:

  1. Step 1: Find the value of one unit. This is done by dividing the given total value by the number of units.
  2. Step 2: Find the value of the required number of units. This is done by multiplying the value of one unit (found in Step 1) by the required number of units.

This method is widely used in everyday situations and problems involving cost and quantity, distance and time (at a constant speed), work and time (at a constant rate), etc.


Steps of the Unitary Method (General Procedure)

Let's formalise the steps. Suppose you are given that 'n' items (or units) have a total value of 'V'. You need to find the value of 'm' items (or units).

  1. Step 1: Find the value of one item (the unit value). Divide the total given value (V) by the number of items (n) to get the value per item.

    $\text{Value of 1 item} = \frac{\text{Total Value (V)}}{\text{Number of items (n)}}$

    The result of this step tells you the value corresponding to a single unit quantity.

  2. Step 2: Find the value of the required number of items. Multiply the value of 1 item (found in Step 1) by the required number of items (m).

    $\text{Value of m items} = (\text{Value of 1 item}) \times \text{Number of required items (m)}$

    This step scales the unit value up to the desired quantity.

The success of the unitary method relies on the relationship between the quantities being directly proportional, meaning the ratio between the value and the number of units remains constant.


Example 1. If the cost of 5 pens is $\textsf{₹}60$, what is the cost of 8 pens?

Answer:

We are given the cost of a certain number of pens (5 pens) and need to find the cost of a different number of pens (8 pens). This is a classic problem solvable by the unitary method.

Given: Cost of 5 pens $= \textsf{₹}60$.

We need to find: Cost of 8 pens.

Step 1: Find the cost of 1 pen.

If 5 pens cost $\textsf{₹}60$, then the cost of a single pen is the total cost divided by the number of pens.

$\text{Cost of 1 pen} = \frac{\text{Total cost}}{\text{Number of pens}}$

$= \frac{\textsf{₹}60}{5}$

Perform the division:

$= \textsf{₹}12$

So, the cost of 1 pen is $\textsf{₹}12$. This is the value of the 'unit'.

Step 2: Find the cost of 8 pens.

Now that we know the cost of 1 pen is $\textsf{₹}12$, we can find the cost of 8 pens by multiplying the cost per pen by the number of pens required.

$\text{Cost of 8 pens} = (\text{Cost of 1 pen}) \times 8$

$= \textsf{₹}12 \times 8$

Perform the multiplication:

$= \textsf{₹}96$

The cost of 8 pens is $\textsf{₹}96$.

Using the unitary method, we found that 8 pens would cost $\textsf{₹}96$.


Example 2. A car travels 150 km in 3 hours. How far will it travel in 5 hours at the same speed?

Answer:

We are given the distance traveled in a certain time (3 hours) and need to find the distance traveled in a different time (5 hours). Assuming the speed is constant, this is a direct proportion problem solvable by the unitary method.

Given: Distance traveled in 3 hours = 150 km.

We need to find: Distance traveled in 5 hours.

Step 1: Find the distance traveled in 1 hour.

If the car travels 150 km in 3 hours, the distance covered in a single hour (which is the speed) is the total distance divided by the time taken.

$\text{Distance in 1 hour} = \frac{\text{Total distance}}{\text{Time taken}}$

$= \frac{150 \text{ km}}{3 \text{ hours}}$

Perform the division:

$= 50 \text{ km/hour}$

The car travels 50 km in 1 hour. This is the 'unit distance' per hour.

Step 2: Find the distance traveled in 5 hours.

Now that we know the distance covered in 1 hour is 50 km, we can find the distance covered in 5 hours by multiplying the distance per hour by the required number of hours.

$\text{Distance in 5 hours} = (\text{Distance in 1 hour}) \times 5$

$= 50 \text{ km/hour} \times 5 \text{ hours}$

Perform the multiplication:

$= 250 \text{ km}$

The car will travel 250 km in 5 hours.

Connection to Proportion:

We can also solve this using proportion. Let the unknown distance traveled in 5 hours be $x$ km. The ratio of distance to time should be constant.

Ratio of distance to time in the first case $= 150 \text{ km} : 3 \text{ hours}$.

Ratio of distance to time in the second case $= x \text{ km} : 5 \text{ hours}$.

Since the speed is constant, these ratios are in proportion:

$150:3 :: x:5$

Using the Rule of Proportion (Product of Extremes = Product of Means):

$150 \times 5 = 3 \times x$

$750 = 3x$

Divide both sides by 3:

$x = \frac{750}{3}$

$x = 250$

So, the distance traveled in 5 hours is 250 km. This confirms the result obtained using the unitary method.